Download Algebraic Topology via Differential Geometry by M. Karoubi, C. Leruste PDF

By M. Karoubi, C. Leruste

During this quantity the authors search to demonstrate how equipment of differential geometry locate program within the learn of the topology of differential manifolds. must haves are few because the authors take pains to set out the speculation of differential varieties and the algebra required. The reader is brought to De Rham cohomology, and particular and targeted calculations are current as examples. subject matters coated contain Mayer-Vietoris specified sequences, relative cohomology, Pioncare duality and Lefschetz's theorem. This publication might be compatible for graduate scholars taking classes in algebraic topology and in differential topology. Mathematicians learning relativity and mathematical physics will locate this a useful advent to the suggestions of differential geometry.

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Are zero. What remains can be rewritten using = 0 d(d(f dCda) T , ^ . 2) f, dx dx ) ; (cf. a e 0 (U) . £- * v Now dx n = ( - 1 ) P dxT A dfi (iv) (1) Take with A n da A g = ( da dx X Jd a i A The second double sum i s none o t h e r £ A J . 7). + f d(dg) = dfA dg b e c a u s e of (iii) and ( 1 ) . Then dg) ) = d ( d f A dg) = d(df) A dg - df A d(dg) = 0 and d(da) = O. (3) Write any 1 < deg y. Suppose k > 2 and ( i v ) e s t a b l i s h e d up t o d e g r e e k r a £ J2 (U) a s a = £ B. Ay. with 1 < deg B.

That the differential of a constant form of any degree be zero. Proof: I Uniqueness Let d and 6 be two maps which s a t i s f y a l l the conditions. ,n , (2) Let SI (U) because of (v) . In p a r t i c u l a r , dx. = <5x. a = n n [ a . dx. = £ a. Sx. e SI (0) x 1 i=l 1 i=l 1 where a. e SI (U) . x Because of ( i i ) , ( i i i ) and (iv) , da = n /, = I (da d (a. ) y da 1=1 X ,0 A dx± + (-1) A a dtdxj) dx. Similarly Sa = n £ {a. A 6x. 1 whence da = 6a because of (1). (3) Take an integer up to degree a = £ g.

H e with a. = . . = a. = 1, a. = 0 25 Finally, as with tensor algebras, a linear map induces a homomorphism between e x t e r i o r algebras: Let any integer E,F be two vector spaces, k > 1, A k (f) f : E -> F a linear map. A f f x ^ . 14 Theorem: These maps are linear and their direct sum defines the unique homomorphism of algebras which makes the following diagram commutative: A(E) A(f) Proof: Straightforward: here 9 f(x) = f(x) A f(x) = 0. SYMMETRIC POWERS. SYMMETRIC ALGEBRA Having dealt with skew-symmetric maps, one could expect that amongst k-linear maps plain symmetric maps would behave 'even b e t t e r ' .

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